Kuan滤波C++实现(结合opencv)

void Kuan(Mat &src, Mat &dst,int n)
{
    
    
    for( int i = (n-1)/2; i < src.rows-(n-1)/2; ++i)
       for( int j = (n-1)/2; j < src.cols-(n-1)/2 ; ++j )
          {
              int temp=(src.at<uchar>(i,j)+src.at<uchar>(i-1,j-1)+src.at<uchar>(i-1,j)+src.at<uchar>(i,j-1)
                  +src.at<uchar>(i+1,j)+src.at<uchar>(i,j+1)+src.at<uchar>(i+1,j+1)+src.at<uchar>(i-1,j+1)+src.at<uchar>(i+1,j-1))/9;
              
              int temp_devation=sqrt((double) ((src.at<uchar>(i,j)-k)*(src.at<uchar>(i,j)-k)
                                 +(src.at<uchar>(i-1,j-1)-k)*(src.at<uchar>(i-1,j-1)-k)
                                 +(src.at<uchar>(i-1,j)-k)*(src.at<uchar>(i-1,j)-k)

                                 +(src.at<uchar>(i,j-1)-k)*(src.at<uchar>(i,j-1)-k)
                                 +(src.at<uchar>(i+1,j)-k)*(src.at<uchar>(i+1,j)-k)
                                 +(src.at<uchar>(i,j+1)-k)*(src.at<uchar>(i,j+1)-k)

                                 +(src.at<uchar>(i+1,j+1)-k)*(src.at<uchar>(i+1,j+1)-k)
                                 +(src.at<uchar>(i-1,j+1)-k)*(src.at<uchar>(i-1,j+1)-k)
                                 +(src.at<uchar>(i+1,j-1)-k)*(src.at<uchar>(i+1,j-1)-k))/9);
             
              double w=(double)(d*d)/(d*d+temp_devation*temp_devation);
            
            
               dst.at<uchar>(i,j)=temp+w*(k-temp);
            
          }




}
原文地址:https://www.cnblogs.com/chchche/p/2815305.html