1065. A+B and C (64bit)

1065. A+B and C (64bit) (20)

时间限制

100 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

HOU, Qiming

Given three integers A, B and C in [-2⁶³, 2⁶³], you are supposed to tell whether A+B > C.

Input Specification:

The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line "Case #X: true" if A+B>C, or "Case #X: false" otherwise, where X is the case number (starting from 1).

Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: false
Case #2: true
Case #3: false

 1 #include<stdio.h>
 2 #include<math.h>
 3 #include<stdlib.h>
 4 #include<string.h>
 5 
 6 int main()
 7 {
 8     int i, t;
 9     scanf("%d", &t);
10     long long a, b, c;
11     for(i = 1; i <= t; i++)
12     {
13         scanf("%lld%lld%lld", &a, &b, &c);
14         long long sum = a + b;
15         if(a > 0 && b > 0 && sum < 0)
16             printf("Case #%d: true
", i);
17         else if(a < 0 && b < 0 && sum >= 0)
18             printf("Case #%d: false
", i);
19         else if(sum > c)
20             printf("Case #%d: true
", i);
21         else
22             printf("Case #%d: false
", i);
23     }
24     return 0;
25 }