Python+Selenium学习笔记2

跟着网络课程学了几个小程序。

1.判断a字符串是否为b字符串的子串

 1 # coding = utf-8
 2 
 3 # 判断str_a字符串是否为str_b字符串的子串
 4 
 5 str_a = "欢迎"
 6 str_b = "欢迎大家的到来"
 7 
 8 
 9 def is_sub_str(sub_strs, strs):
10     """
11     判断sub_strs是否为strs的子串
12     :param sub_strs: 待判断的子串
13     :param strs: 父串
14     :return: False|True
15     """
16     if str_a in str_b:
17         return True
18     else:
19         return False
20 
21 
22 a = is_sub_str(str_a, str_b)
23 print(a)

2.对字符串进行循环右移操作，移动n步

 1 # coding = utf-8
 2 
 3 def right_move(strs, n_steps):
 4     """对strs进行循环右移操作，移动n_strs步
 5     :param strs: 待移动的串
 6     :param n_steps: 移动步数
 7     :return: 移动后的串 strs
 8     """
 9     length = len(strs)
10     if length == 0:
11         return strs
12     ret_strs = strs[-n_steps:]+strs[:-n_steps]
13     return ret_strs
14 
15 move = right_move("abcdefg",1)
16 print(move)

3.判断sub_str是否为strs循环右移后的串的子串(调用前两个的函数)

 1 # coding = utf-8
 2 
 3 str_a = "欢迎"
 4 str_b = "欢迎大家来到动脑学院"
 5 
 6 # 判断sub_strs是否为strs的子串
 7 def is_sub_str(sub_strs, strs):
 8     """
 9     判断sub_strs是否为strs的子串
10     :param sub_strs: 待判断的子串
11     :param strs: 父串
12     :return: False|True
13     """
14     if str_a in str_b:
15         return True
16     else:
17         return False
18 
19 
20 # 判断str_a是否为str_b通过循环右移N位产生的串的子串
21 def right_move(strs, n_steps):
22     """
23     对strs进行循环右移操作，移动n_strs步
24     :param strs: 待移动的串
25     :param n_steps: 移动步数
26     :return: 移动后的串 strs
27     """
28     length = len(strs)
29     if length == 0:
30         return strs
31     ret_strs = strs[-n_steps:]+strs[:-n_steps]
32     return ret_strs
33 
34 
35 def can_rotate_get_substrs(strs, sub_str):
36     """
37     判断sub_str是否为strs循环右移后的串的子串
38     :param strs:
39     :param sub_str:
40     :return:
41     """
42     length = len(strs)
43     for i in range(length):
44         if is_sub_str(sub_str, right_move(strs, 1)):
45             return True
46     return False
47 
48 
49 flag = can_rotate_get_substrs(str_b, str_a)
50 print(flag)