tree

          <a  href="javascript:void(0)" onclick="saveChecked()()" class="easyui-linkbutton" iconcls="icon-save">@webmodel.GetLableLanguageName("EPS_LAB_Save")</a>
             <a  href="javascript:void(0)" onclick="initializeMenu()()" class="easyui-linkbutton" iconcls="iconCls:'icon-undo'">@webmodel.GetLableLanguageName("EPS_LAB_Cancel")</a>
                <a  href="javascript:void(0)" onclick="back()()" class="easyui-linkbutton" data-options="iconCls:'icon-back'">@webmodel.GetLableLanguageName("EPS_LAB_Back")</a>
    <a href="javascript:void(0)" class="easyui-linkbutton" iconcls="icon-save" plain="true"
        onclick="save()">@webmodel.GetLableLanguageName("EPS_LAB_Save")</a>

以前是ViewData
MVC3中 ViewBag使用类似属性访问的语法检索字典中的值   ViewBag.Message等同于ViewData

["Message"]

<img src="@Url.Content("~/Content/Base/Images/Manpower.gif")" alt="" title=""

onclick="operation_permitedit(\''+rec.RoleID+'\')"/>';


 1 //获取所有树叶子节点 注册添加事件 if ($(node).tree('isLeaf', node.target)) 是否叶子

节点
 2 $(function () {
 3 $('.easyui-tree').tree({
 4 onClick: function (node) {
 5 if ($(node).tree('isLeaf', node.target)) {
 6 alert(node.text);
 7 }
 8 }
 9 })
10
11 })


 easyui获取树实心节点数据方式
2013-09-16 10:09 66人阅读 评论(0) 收藏 举报
var nodes3 = $('#Tree').tree('getChecked', 'indeterminate'); //获取模糊不清的

/*获取树节点数据*/
function getChecked(p){
var nodes = p.find('form #functionlist').tree('getChecked');
var s = '';
for(var i=0; i<nodes.length; i++){
if (s != '') s += ',';
s += nodes[i].id;
}
var fatherNodes =  p.find('form #functionlist').tree('getChecked', 'indeterminate'); //

获取模糊不清的父亲节点即实心节点
for(var i=0; i<fatherNodes.length; i++){
if (s != '') s += ',';
s += fatherNodes[i].id;
}
return s;//包括所有的节点
}
更多 0
上一篇:mybatis多对多关

<a href="javascript:;" onclick="document.form.submit();"><img src="login_08.gif" width="50" height="35" /></a>
1 var nodes = [];
2  $("#Tree").find('.tree-checkbox2').each(function(){
3         var node = $(this).parent();
4         nodes.push($.extend({}, $.data(node[0], 'tree-node'), {
5                 target: node[0],
6                 checked: node.find('.tree-checkbox').hasClass('tree-checkbox2')
7         }));
8 });
1

nodes 就是有像图上那样的实心节点。是通过$("#Tree").tree("getChecked");方法获取不到的。

扩展easyui tree的两个方法 获取实心节点

发表于1年前(2012-07-06 09:55)   阅读(686) | 评论(0 0人收藏此文章, 我要收藏
0
01 $.extend($.fn.tree.methods,{
02     getCheckedExt: function(jq){
03         var checked = $(jq).tree("getChecked");
04         var checkbox2 = $(jq).find("span.tree-checkbox2").parent();
05         $.each(checkbox2,function(){
06             var node = $.extend({}, $.data(this, "tree-node"), {
07                 target : this
08             });
09             checked.push(node);
10         });
11         return checked;
12     },
13     getSolidExt:function(jq){
14         var checked =[];
15         var checkbox2 = $(jq).find("span.tree-checkbox2").parent();
16         $.each(checkbox2,function(){
17             var node = $.extend({}, $.data(this, "tree-node"), {
18                 target : this
19             });
20             checked.push(node);
21         });
22         return checked;
23     }
24 });
原文地址:https://www.cnblogs.com/gycnet/p/3437437.html