scala读取解析json文件

import scala.util.parsing.json.JSON._
import scala.io.Source

object ScalaJsonParse {
  def main(args: Array[String]): Unit = {

    var tt =  Map.empty[String, Any]

    val tree = parseFull(Source.fromFile("/data/result.json").mkString)
    tt = tree match {
      case Some(map: Map[String, Any]) => map
    }
    println(tt.getClass.getSimpleName)

  }
}

得到的结果如下:

HashTrieMap
原文地址:https://www.cnblogs.com/TTyb/p/6656258.html