sql获取当前月份的前一月,当前天的前一天,当前年的前一年

当前年份加减:

SELECT CONVERT(varchar(12),DATEADD(year,1,GETDATE()),23) as year
SELECT CONVERT(varchar(12),DATEADD(year,-1,GETDATE()),23) as year

 

当前月份的加减:

SELECT CONVERT(varchar(12),DATEADD(MONTH,1,GETDATE()),23) as month
SELECT CONVERT(varchar(12),DATEADD(MONTH,-1,GETDATE()),23) as month

  

当前天的加减:

SELECT CONVERT(varchar(12),DATEADD(DAY,1,GETDATE()),23) as day
SELECT CONVERT(varchar(12),DATEADD(DAY,-1,GETDATE()),23) as day

  

原文地址:https://www.cnblogs.com/Angel-szl/p/10431806.html