Python——二分法查找

#递归实现二分法查找
data=[1,3,6,7,9,12,14,16,17,18,20,21,22,23,30,32,33,35]
def binary_search(dataset,find_num):
    print(dataset)

    if len(dataset) > 1:
        mid = int(len(dataset)/2)
        if dataset[mid]==find_num:
            print("找到数字",dataset[mid])
        elif dataset[mid] >find_num :
            print("33[31;1m找到的数在mid[%s]左面33[0m"% dataset[mid])
            return binary_search(dataset[0:mid],find_num)
        else:
            print("33[32;1m找的数在mid[%s]右面33[0m"% dataset[mid])
            return binary_search(dataset[mid+1:],find_num)
    else:
        if dataset[0]==find_num:
            print("找到数字啦",dataset[0])
        else:
            print("要找的数字[%s]不在列表里"%find_num)
binary_search(data,33)
原文地址:https://www.cnblogs.com/zhaoxiaoxue/p/11194482.html