UVA-11462 (计数排序)

题意:

2e6个数,按从小到大的顺序输出;

思路:

计数排序;

AC代码:

#include <bits/stdc++.h>
/*
#include <vector>
#include <iostream>
#include <queue>
#include <cmath>
#include <map>
#include <cstring>
#include <algorithm>
#include <cstdio>
*/
using namespace std;
#define For(i,j,n) for(int i=j;i<=n;i++)
#define Riep(n) for(int i=1;i<=n;i++)
#define Riop(n) for(int i=0;i<n;i++)
#define Rjep(n) for(int j=1;j<=n;j++)
#define Rjop(n) for(int j=0;j<n;j++)
#define mst(ss,b) memset(ss,b,sizeof(ss));
typedef  long long LL;
template<class T> void read(T&num) {
    char CH; bool F=false;
    for(CH=getchar();CH<'0'||CH>'9';F= CH=='-',CH=getchar());
    for(num=0;CH>='0'&&CH<='9';num=num*10+CH-'0',CH=getchar());
    F && (num=-num);
}
int stk[70], tp;
template<class T> inline void print(T p) {
    if(!p) { puts("0"); return; }
    while(p) stk[++ tp] = p%10, p/=10;
    while(tp) putchar(stk[tp--] + '0');
    putchar('
');
}

const LL mod=1e9+7;
const double PI=acos(-1.0);
const LL inf=1e18;
const int N=3e5+10;
const int maxn=1005;
const double eps=1e-10;



int n,m;
int a[104];

int main()
{

        while(1)
        {
            mst(a,0);
            read(n);
            int x;
            if(!n)break;
            For(i,1,n)read(x),a[x]++;
            For(i,1,100)
            {
                while(a[i]--)
                {
                    n--;
                    printf("%d",i);
                    if(n>=1)printf(" ");
                    else printf("
");
                }
            }
        }
        return 0;
}
原文地址:https://www.cnblogs.com/zhangchengc919/p/5662418.html