剑指offer python版 从尾到头打印链表

class ListNode(object):
    def __init__(self,x):
        self.val=x
        self.next=None
        
class Link(object):
    def __init__(self,values=None):
        self.nodes=self.set_link(values) if  values else None
        
    def get_link(self):
        return self.nodes
    def set_link(self,values):
        if not values :
            return False
        head=ListNode(0)
        move=head
        
        
        try:
            for i in values:
                tmp=ListNode(i)
                move.next=tmp
                move=move.next
                
        except Exception as e:
            print(e)
            
        return head.next
    
    def print_link(self):
        head=self.nodes
        stack=[]
        ret=[]
        while head:
            stack.append(head.val)
            head=head.next
            
        while stack:
            ret.append(stack.pop())
            
        return ret
    
a=Link([1,2,3,4,5])

b=a.get_link()


print(a.print_link())
原文地址:https://www.cnblogs.com/xzm123/p/9847906.html