例3-5

#include<stdio.h>
int main(void)
{
    double value1,value2;
    char op;
    printf("Type in an expression:");
    scanf("%lf%c%lf",&value1,&op,&value2);


    if(op=='+')
        printf("=%.2f
",value1+value2);
    else if(op=='-')
        printf("=%.2f
",value1-value2);
    else if(op=='*')
        printf("=%.2f
",value1*value2);
    else if(op=='/')
        printf("=%.2f
",value1/value2);
    else
        printf("Unknown operator
");


    return 0;

原文地址:https://www.cnblogs.com/xym0914/p/3350355.html