poj 3071 Football 概率DP

概率DP,递推式:dp[i][j]=sigma(dp[i-1][j]*p[j][k]*dp[i-1][k])

再就是判断j和k是否相邻:if(((k>>(i-1))^1)==(j>>(i-1)))

代码如下:

#include<iostream>
#include<stdio.h>
#include<algorithm>
#include<iomanip>
#include<cmath>
#include<cstring>
using namespace std;
double dp[129][129],p[129][129];
int main()
{
    int i,j,k,ans,n;
    while(cin>>n){
        if(n==-1) break;
        for(i=0;i<(1<<n);i++)
        for(j=0;j<(1<<n);j++){
            cin>>p[i][j];
        }
        memset(dp,0,sizeof(dp));
        for(i=0;i<(1<<n);i++) dp[0][i]=1;
        for(i=1;i<=n;i++)
        for(j=0;j<(1<<n);j++)
        for(k=0;k<(1<<n);k++){
            if(((k>>(i-1))^1)==(j>>(i-1)))
                dp[i][j]+=dp[i-1][j]*dp[i-1][k]*p[j][k];
        }
        ans=0;
        for(i=0;i<(1<<n);i++)
            if(dp[n][i]>dp[n][ans])
                ans=i;
        cout<<ans+1<<endl;
    }
}
View Code
原文地址:https://www.cnblogs.com/xin-hua/p/3233427.html