图--二分匹配模板

#include "stdio.h"  // 二分匹配 hdu 2063
#include "string.h"
#define N 1005
int n,m;

bool mark[N];
int map[N][N],route[N];
int find(int a) //找增广路
{
	int i;
	for(i=1;i<=m;i++)
	{
		if(map[a][i]==1 && mark[i]==false)
		{
			mark[i] = 1;
			if(route[i]==0 || find(route[i])==1)//如果i没有匹配,直接跟a匹配,如果有匹配,找link[i]的增广路
			{
				route[i] = a;
				return 1;
			}
		}
	}
	return 0;
}

int main()
{
	int i,t,x,y,sum;
	while(scanf("%d",&t),t)
	{
		sum = 0;
		scanf("%d%d",&n,&m);
		memset(map,0,sizeof(map));
		memset(route,0,sizeof(route));
		for(i=1;i<=t;i++)
		{
			scanf("%d%d",&x,&y);
			map[x][y] = 1;
		}
		for(i=1;i<=n;i++)
		{
			memset(mark,false,sizeof(mark));
			sum += find(i);
		}
		printf("%d
",sum);
	}
	return 0;
}

原文地址:https://www.cnblogs.com/ruo-yu/p/4412001.html