分数排名

Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" between ranks.

+----+-------+
| Id | Score |
+----+-------+
| 1  | 3.50  |
| 2  | 3.65  |
| 3  | 4.00  |
| 4  | 3.85  |
| 5  | 4.00  |
| 6  | 3.65  |
+----+-------+

For example, given the above Scores table, your query should generate the following report (order by highest score):

+-------+------+
| Score | Rank |
+-------+------+
| 4.00  | 1    |
| 4.00  | 1    |
| 3.85  | 2    |
| 3.65  | 3    |
| 3.65  | 3    |
| 3.50  | 4    |
+-------+------+

分数排名 - LeetCode (中国) https://leetcode-cn.com/problems/rank-scores/description/

 优化 简化  

SELECT s.Score,tt.Rank FROM Scores s LEFT JOIN

(
SELECT (@i:=@i+1) Rank,t.* FROM (SELECT COUNT(Id) AS c,Score FROM Scores GROUP BY Score ORDER BY Score DESC ) AS t , (SELECT @i:=0) AS a
) AS tt ON s.Score=tt.Score ORDER BY Rank ASC;

原文地址:https://www.cnblogs.com/rsapaper/p/9094645.html