VUE检查用户名复杂性、手机号是否合法、密码的复杂度

1.vue检查用户名是否重复

  • 前端函数如下,js方法代码无需更改,前端代码逻辑在componentscommonlab_header.vue

  • 只需要修改componentsaxios_apihttp.js中调用的后端地址

// axios.defaults.baseURL = "http://127.0.0.1:8000/"
axios.defaults.baseURL = "http://192.168.56.100:8888/"
    // 检查用户名 是否使用
    check_username() {
      console.log('判断用户名')
      console.log(this.username == '')
      var reg = new RegExp(/^[a-zA-Z0-9_-]{3,16}$/); //字符串正则表达式 4到14位(字母,数字,下划线,减号)
      if (this.username == '') {
        this.username_message = '用户名不能为空'
        this.username_error = true
        return false
      }
      if (!reg.test(this.username)) {
        this.username_message = '用户名格式不正确'
        this.username_error = true
        return false
      } else {
        // 去后端检查用户名使用数量
        user_count({ type: 'username', data: this.username }).then((res) => {
          console.log(res)
          if (res.data.count > 0) {
            this.username_message = '用户名已存在'
            this.username_error = true
          } else {
            this.username_message = ''
            this.username_error = false
          }
        })
      }
    },

2.vue检查手机号是否重复

    // 检查手机号是否使用
    check_phone() {
      console.log('检查手机号')
      var reg = new RegExp(/^[1]([3-9])[0-9]{9}$/)
      if (this.phone == '') {
        this.phone_message = '手机号不能为空'
        this.phone_error = true
      }

      if (!reg.test(this.phone)) {
        this.phone_message = '手机号格式不正确'
        this.phone_error = true
        return false
      } else {
        // 去后端查用户数量
        user_count({ type: 'phone', data: this.phone }).then((res) => {
          console.log(res)
          if (res.data.count > 0) {
            this.phone_message = '手机号已存在'
            this.phone_error = true
          } else {
            this.phone_message = ''
            this.phone_error = false
          }
        })
      }
    },

 3.VUE检查密码的复杂度

// 检查密码是否正确
    check_password() {
      console.log('检查两遍密码')
      // debugger
      if (this.password == '') {
        this.password_message = '密码不能为空'
        this.password_error = true
        return false
      }
      if (this.password != this.password2) {
        this.password_message = '两遍密码不一致'
        this.password_error = true
        return false
      }
      if (this.password.length < 6) {
        this.password_message = '密码长度不能小于6位'
        this.password_error = true
        return false
      }
      this.password_message = ''
      this.password_error = false
    },

 

原文地址:https://www.cnblogs.com/pythonqwertytre/p/13782302.html