126或163邮箱需要登录发送邮件的邮箱--设置--开启客户端授权密码后才能正常发送邮件
#!/usr/bin/python3
import smtplib
from email.mime.text import MIMEText
import time
def sendmsg(data):
email_host = 'smtp.126.com' #邮箱地址
email_user = 'xxxx@126.com' # 发送者账号
email_pwd = 'xxxx' # 发送者的密码
maillist ='xxxx@qq.com'
#收件人邮箱,多个账号的话,用逗号隔开
me = email_user
msg = MIMEText(data) # 可直接写邮件内容,也可以是变量,这里的data是变量
msg['Subject'] = 'orderinsert' # 邮件主题
msg['From'] = me # 发送者账号
msg['To'] = maillist # 接收者账号列表
smtp = smtplib.SMTP(email_host,port=25) # 连接邮箱,传入邮箱地址,和端口号,smtp的端口号是25
smtp.login(email_user, email_pwd) # 发送者的邮箱账号,密码
smtp.sendmail(me, maillist, msg.as_string())
# 参数分别是发送者,接收者,第三个是把上面的发送邮件的内容变成字符串
smtp.quit() # 发送完毕后退出smtp
jkwb = './ceshi/msg.txt'
f = open(jkwb, "r")
data0 = f.read()
f.close()
while True:
f = open(jkwb, "r")
data = f.read()
f.close
if data0 != data:
sendmsg(data)
data0 = data
time.sleep(1)
print ('email send success.')