PAT 1050. 螺旋矩阵(25)

要想解决本题,要解决以下几个问题:

1. 获得准确的m、n

2. 按照题目的要求,以顺时针螺旋的方式安放元素

代码如下:

#include <iostream>
#include <vector>
#include <algorithm>

using namespace std;

int m , n;

void Findmn(int N)
{
	int i , j;
	for(i = 2 ; i * i <= N ; i++)
	{
		if(N % i == 0)
		{
			j = N / i;
			if(abs(m - n) > abs (i - j))
			{
				m = max(i , j);
				n = min(i , j);
			}
		}
	}
}

bool cmp(int a , int b)
{
	return a > b;
}

int main()
{
	int N;
	cin>>N;
	vector<int> Nums(N);
	int i,j;
	for(i = 0 ; i < N ; i++)
		cin>>Nums[i];
	sort(Nums.begin(),Nums.end(),cmp);
	m = N;
	n = 1;
	Findmn(N);
	vector<vector<int> > W(m);
	for(i = 0 ; i < m ; i++)
		W[i].assign(n,0);
	int m1 = m -1, n1 = n , m2 , n2;
	vector<int> dx(N),dy(N);
	i = 0;
	if(N == 1)
		cout<<Nums[0]<<endl;
	else
	{
		while(n1)
		{
			n2 = n1;
			while(n2--)
			{
				dx[i] = 0;
				dy[i++] = 1;
			}
			n1--;
			m2 = m1;
			while(m2--)
			{
				dx[i] = 1;
				dy[i++] = 0;
			}
			m1--;
			if(n1 == 0)
				break;
			n2 = n1;
			while(n2--)
			{
				dx[i] = 0;
				dy[i++] = -1;
			}
			n1--;
			m2 = m1;
			while(m2--)
			{
				dx[i] = -1;
				dy[i++] = 0;
			}
			m1--;
		}
		int x1 = 0 , y1 = -1;
		for(i = 0 ; i < N ; i ++)
		{
			x1 += dx[i];
			y1 += dy[i];
			W[x1][y1] = Nums[i];
		}
		for(i = 0 ; i < m ; i++)
		{
			cout<<W[i][0];
			for(j = 1 ; j < n ; j++)
			{
				cout<<' '<<W[i][j];
			}
			cout<<endl;
		}
	}

	system("pause");
}



原文地址:https://www.cnblogs.com/hkevin/p/5510064.html