将金额人民币转化为大写 C#

什么也不说了，直接上代码 
 1 /// <summary>
  2 /// 转换人民币大小金额
  3 /// </summary>
  4 /// <param name="num">金额</param>
  5 /// <returns>返回大写形式</returns>
  6 public static string CmycurD(decimal num)
  7 {
  8 string str1 = "零壹贰叁肆伍陆柒捌玖"; //0-9所对应的汉字
  9 string str2 = "万仟佰拾亿仟佰拾万仟佰拾元角分"; //数字位所对应的汉字
 10 string str3 = ""; //从原num值中取出的值
 11 string str4 = ""; //数字的字符串形式
 12 string str5 = ""; //人民币大写金额形式
 13 int i; //循环变量
 14 int j; //num的值乘以100的字符串长度
 15 string ch1 = ""; //数字的汉语读法
 16 string ch2 = ""; //数字位的汉字读法
 17 int nzero = 0; //用来计算连续的零值是几个
 18 int temp; //从原num值中取出的值
 20 num = Math.Round(Math.Abs(num), 2); //将num取绝对值并四舍五入取2位小数
 21 str4 = ((long)(num * 100)).ToString(); //将num乘100并转换成字符串形式
 22 j = str4.Length; //找出最高位
 23 if (j > 15) { return "溢出"; }
 24 str2 = str2.Substring(15 - j); //取出对应位数的str2的值。如：200.55,j为5所以str2=佰拾元角分
 25 
 26 //循环取出每一位需要转换的值
 27 for (i = 0; i < j; i++)
 28 {
 29 str3 = str4.Substring(i, 1); //取出需转换的某一位的值
 30 temp = Convert.ToInt32(str3); //转换为数字
 31 if (i != (j - 3) && i != (j - 7) && i != (j - 11) && i != (j - 15))
 32 {
 33 //当所取位数不为元、万、亿、万亿上的数字时
 34 if (str3 == "0")
 35 {
 36 ch1 = "";
 37 ch2 = "";
 38 nzero = nzero + 1;
 39 }
 40 else
 41 {
 42 if (str3 != "0" && nzero != 0)
 43 {
 44 ch1 = "零" + str1.Substring(temp * 1, 1);
 45 ch2 = str2.Substring(i, 1);
 46 nzero = 0;
 47 }
 48 else
 49 {
 50 ch1 = str1.Substring(temp * 1, 1);
 51 ch2 = str2.Substring(i, 1);
 52 nzero = 0;
 53 }
 54 }
 55 }
 56 else
 57 {
 58 //该位是万亿，亿，万，元位等关键位
 59 if (str3 != "0" && nzero != 0)
 60 {
 61 ch1 = "零" + str1.Substring(temp * 1, 1);
 62 ch2 = str2.Substring(i, 1);
 63 nzero = 0;
 64 }
 65 else
 66 {
 67 if (str3 != "0" && nzero == 0)
 68 {
 69 ch1 = str1.Substring(temp * 1, 1);
 70 ch2 = str2.Substring(i, 1);
 71 nzero = 0;
 72 }
 73 else
 74 {
 75 if (str3 == "0" && nzero >= 3)
 76 {
 77 ch1 = "";
 78 ch2 = "";
 79 nzero = nzero + 1;
 80 }
 81 else
 82 {
 83 if (j >= 11)
 84 {
 85 ch1 = "";
 86 nzero = nzero + 1;
 87 }
 88 else
 89 {
 90 ch1 = "";
 91 ch2 = str2.Substring(i, 1);
 92 nzero = nzero + 1;
 93 }
 94 }
 95 }
 96 }
 97 }
 98 if (i == (j - 11) || i == (j - 3))
 99 {
100 //如果该位是亿位或元位，则必须写上
101 ch2 = str2.Substring(i, 1);
102 }
103 str5 = str5 + ch1 + ch2;
104 
105 if (i == j - 1 && str3 == "0")
106 {
107 //最后一位（分）为0时，加上“整”
108 str5 = str5 + '整';
109 }
110 }
111 if (num == 0)
112 {
113 str5 = "零元整";
114 }
115 return str5;
116 }