Leetcode-204 Count Primes

#204 Count Primes

Count the number of prime numbers less than a non-negative number, n.

题解:这道题如果对每个小于n的数都进行判断是否为素数并计数会超时,因此采用筛法来解这题。建一个数组,从2开始, 把其倍数小于N的都删掉。

class Solution {
public:
    int countPrimes(int n) {
        vector<int>arr(n,1);
        int sum=0;
        for(int i=2;i<=n;i++)
        {
            if(arr[i]==1)
            {
                sum++;
                for(int j=i;j<n;j+=i)
                {
                    arr[j]=0;
                }
            }
 
        }
        return sum;
    }
};
原文地址:https://www.cnblogs.com/fengxw/p/6061597.html