【小米oj】在一个有序的经过旋转的数组里查找一个数

 1 #define mm(a) memset(a,0,sizeof(a));
 2 #define max(x,y) (x)>(y)?(x):(y)
 3 #define min(x,y) (x)<(y)?(x):(y)
 4 #define Fopen freopen("1.in","r",stdin); freopen("m.out","w",stdout);
 5 #define rep(i,a,b) for(int i=(a);i<=(b);i++)
 6 #define per(i,b,a) for(int i=(b);i>=(a);i--)
 7 #include<bits/stdc++.h>
 8 typedef long long ll;
 9 #define PII pair<ll,ll>
10 using namespace std;
11 const int INF=0x3f3f3f3f;
12 const int MAXN=(int)2e5 + 5;
13 const ll mod=1e9+7;
14 
15 
16 string input,temp;
17 vector<int>v;
18 map<int,int>mp;
19 int n,dp[MAXN],m,x;
20 int main() {
21     while (cin >> input) {
22         istringstream iss(input);
23         v.clear();
24         v.push_back(0);
25         while (getline(iss, temp, ',')) {
26             int x=atoi(temp.c_str());
27             v.push_back(x);
28         }
29         n=v.size()-1;
30         for(int i=1;i<=n;i++)mp[v[i]]=i;
31         scanf("%d",&x);
32         printf("%d
",mp[x]-1);
33     }
34     return 0;
35 }