1135: 零起点学算法42——多组测试数据（求和)IV

Time Limit: 1 Sec Memory Limit: 64 MB 64bit IO Format: %lld
Submitted: 2439 Accepted: 1277
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Description

还有一些输入是以上几种情况的组合,具体根据题目对前面几种情况进行组合
比如题目要求是多组测试数据
每组测试数据首先输入一个整数n(如果n=0就表示结束）然后再输入n个整数
这类题目输入格式如下：


int main()

{

    int n,i;

    while(scanf("%d",&n)!=EOF && n!=0)

    {

         for(i=1;i<=n;i++)

         { 

              ....//每次输入一个数，共循环n次，需要的时候做其他处理

         }



    }

}

Input

Input contains multiple test cases. Each test case contains a integer N, and then N integers follow in the same line. A test case starting with 0 terminates the input and this test case is not to be processed.

Output

For each group of input integers you should output their sum in one line, and with one line of output for each line in input.

Sample Input

4 1 2 3 4
5 1 2 3 4 5
0

Sample Output

10
15

Source

零起点学算法

 1 #include<stdio.h>
 2 int main(){
 3     int n;
 4     while(scanf("%d",&n)!=EOF&&n!=0){
 5         int a,s=0;
 6         for(int i=1;i<=n;i++){
 7             scanf("%d",&a);
 8             s+=a;
 9         }
10         printf("%d
",s);
11     }
12     return 0;
13 }