leetcode-86. Partition List


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Definition for singly-linked list. # class ListNode(object): # def __init__(self, x): # self.val = x # self.next = None

class Solution(object): def partition(self, head, x): """ :type head: ListNode :type x: int :rtype: ListNode """ h1=l1=ListNode(None) h2=l2=ListNode(None) while head: if head.val < x: l1.next = head l1 = l1.next else: l2.next = head l2 = l2.next head = head.next l2.next = None l1.next = h2.next return h1.next
原文地址:https://www.cnblogs.com/boluo007/p/10273717.html