Reverse Integer

## Problem

Reverse digits of an integer.

**Example1:** x = 123, return 321
**Example2:** x = -123, return -321

[click to show spoilers.](https://leetcode.com/problems/reverse-integer/#)

**Note:**
The input is assumed to be a 32-bit signed integer. Your function should **return 0 when the reversed integer overflows**.

## Code

    public int reverse(int x){
        long result = 0;
        while(x!=0){
            int temp = x%10;
            result = result*10+temp;
            x/=10;
        }
        if (result>Integer.MAX_VALUE||result
原文地址:https://www.cnblogs.com/bingo2-here/p/7168443.html