bash 算术运算

bash中实现算术运算

1,let var=算术表达式

let num1=1+2
echo $num1

2, var=$[算术表达式]

num2=$[2+3]
echo $num2

3, var=$((算术表达式))

num3=$((2+3))
echo $num3

4, var=$(expr arg1 arg2 arg3 ...)

num4=$(expr 1 + 3)
echo $num4


num5=$(expr $(expr 2 + 3) * 5)
echo $num5


原文地址:https://www.cnblogs.com/baozi-tudou/p/13691807.html