N分成不同的数相乘使答案最大

题意:http://acm.hdu.edu.cn/showproblem.php?pid=5976

首先队友想出了分的越多答案越多。

我们就:2,3,4,5,6.。。多出来的尽量往小了加就行了。

  1 #define IOS ios_base::sync_with_stdio(0); cin.tie(0);
  2 #include <cstdio>//sprintf islower isupper
  3 #include <cstdlib>//malloc  exit strcat itoa system("cls")
  4 #include <iostream>//pair
  5 #include <fstream>//freopen("C:\Users\13606\Desktop\草稿.txt","r",stdin);
  6 #include <bitset>
  7 //#include <map>
  8 //#include<unordered_map>
  9 #include <vector>
 10 #include <stack>
 11 #include <set>
 12 #include <string.h>//strstr substr
 13 #include <string>
 14 #include <time.h>// srand(((unsigned)time(NULL))); Seed n=rand()%10 - 0~9;
 15 #include <cmath>
 16 #include <deque>
 17 #include <queue>//priority_queue<int, vector<int>, greater<int> > q;//less
 18 #include <vector>//emplace_back
 19 //#include <math.h>
 20 #include <cassert>
 21 //#include <windows.h>//reverse(a,a+len);// ~ ! ~ ! floor
 22 #include <algorithm>//sort + unique : sz=unique(b+1,b+n+1)-(b+1);+nth_element(first, nth, last, compare)
 23 using namespace std;//next_permutation(a+1,a+1+n);//prev_permutation
 24 //******************
 25 int abss(int a);
 26 int lowbit(int n);
 27 int Del_bit_1(int n);
 28 int maxx(int a,int b);
 29 int minn(int a,int b);
 30 double fabss(double a);
 31 void swapp(int &a,int &b);
 32 clock_t __STRAT,__END;
 33 double __TOTALTIME;
 34 void _MS(){__STRAT=clock();}
 35 void _ME(){__END=clock();__TOTALTIME=(double)(__END-__STRAT)/CLOCKS_PER_SEC;cout<<"Time: "<<__TOTALTIME<<" s"<<endl;}
 36 //***********************
 37 #define rint register int
 38 #define fo(a,b,c) for(rint a=b;a<=c;++a)
 39 #define fr(a,b,c) for(rint a=b;a>=c;--a)
 40 #define mem(a,b) memset(a,b,sizeof(a))
 41 #define pr printf
 42 #define sc scanf
 43 #define ls rt<<1
 44 #define rs rt<<1|1
 45 typedef vector<int> VI;
 46 typedef long long ll;
 47 const double E=2.718281828;
 48 const double PI=acos(-1.0);
 49 //const ll INF=(1LL<<60);
 50 const int inf=(1<<30);
 51 const double ESP=1e-9;
 52 const int mod=(int)1e9+7;
 53 const int N=(int)1e6+10;
 54 
 55 ll a[N],sum[N],up[N];
 56 int er[17]={1,2,4,8,16,32,64,128,256,512,1024,2048,4096,8192,16384,32768,65536};
 57 ll qpow(ll a,ll b,ll mod)
 58 {
 59     ll ans;
 60 //    a%=mod;
 61     ans=1;
 62     while(b!=0)
 63     {
 64         if(b&1)
 65             ans=(ans*a)%mod;
 66         b/=2;
 67         a=(a*a)%mod;
 68     }
 69     return ans;
 70 }
 71 
 72 int main()
 73 {
 74     sum[1]=2;
 75     up[1]=2;
 76     a[1]=2;
 77     for(int i=2;i<=N-3;++i)
 78         a[i]=i+1,sum[i]=i+1+sum[i-1],up[i]=up[i-1]*(i+1)%mod;
 79     ll x;
 80     int T;
 81     sc("%d",&T);
 82     while(T--)
 83     {
 84         sc("%lld",&x);
 85         if(x<=4)
 86         {
 87             cout<<x<<endl;
 88             continue;
 89         }
 90         int temp=0;
 91         for(int i=16;i>=0;--i)
 92         {
 93             if(sum[temp+er[i]]<=x)
 94                 temp+=er[i];
 95         }
 96         ll out=x%sum[temp];
 97         if(temp+1-out>=1)
 98         {
 99             ll other=up[temp]*qpow(a[out?temp+1-out:temp],mod-2,mod)%mod;
100             ll ans=other*(a[out?temp+1-out:temp]+out)%mod;
101             pr("%lld
",ans);
102         }
103         else
104         {
105             ll other=up[temp]*qpow(2,mod-2,mod)%mod;
106             ll ans=other*(2+out)%mod;
107             pr("%lld
",ans);
108         }
109     }
110     return 0;
111 }
112 
113 /**************************************************************************************/
114 
115 int maxx(int a,int b)
116 {
117     return a>b?a:b;
118 }
119 
120 void swapp(int &a,int &b)
121 {
122     a^=b^=a^=b;
123 }
124 
125 int lowbit(int n)
126 {
127     return n&(-n);
128 }
129 
130 int Del_bit_1(int n)
131 {
132     return n&(n-1);
133 }
134 
135 int abss(int a)
136 {
137     return a>0?a:-a;
138 }
139 
140 double fabss(double a)
141 {
142     return a>0?a:-a;
143 }
144 
145 int minn(int a,int b)
146 {
147     return a<b?a:b;
148 }
原文地址:https://www.cnblogs.com/--HPY-7m/p/11745651.html