求一个整数数组的最大元素,递归方法实现

Java版本:

public class Main {
    public static void main(String[] args) {
        int[] array = {1, 3, 5, 6, 3, 5, 3, 8};
        System.out.println(findMaxValue(array));
    }

    private static int findMaxValue(int[] array) {
        if(array.length <= 0 || array == null) {
            return -1;
        }
        return findMaxValue(array, 0);
        
    }

    private static int findMaxValue(int[] array, int start) {
        int len = array.length - start;
        if( len == 1) {
            return array[start];
        } else {
            return Math.max(array[start], findMaxValue(array, start+1));
        }
    }
}

C++版本:

#include<iostream>
#include<cmath>
using namespace std;
int maxnum(int array[], int n)
{
    if(n == 1)
    {
        return array[0];
    } 
    else 
    {
        return max(array[0], maxnum(array+1,n-1));
    }
}

int main() {
    int num[10] = {0,1,2,3,4,5,6,7,8,9};  
    cout<<maxnum(num,10)<<endl;  
    return 0;  
}
原文地址:https://www.cnblogs.com/zywu/p/5858950.html