LeetCode 4. 寻找两个正序数组的中位数

class Solution {
public:
    double findMedianSortedArrays(vector<int>& nums1, vector<int>& nums2) {
        int tot = nums1.size() + nums2.size();
        if(tot % 2 == 0){
            int left = find(nums1, 0, nums2, 0, tot / 2);
            int right = find(nums1,0,nums2,0, tot /2 +1);
            return (left + right) / 2.0;
        }else
        {
            return find(nums1,0,nums2,0, tot / 2 + 1);
        }
    }

    int find(vector<int>& nums1,int i,vector<int>& nums2, int j,int k)
    {
        if(nums1.size() - i > nums2.size() - j) return find(nums2, j,nums1, i, k);
        if(k == 1)
        {
            if(nums1.size() == i) return nums2[j];
            else return min(nums1[i], nums2[j]);
        }
         if (nums1.size() == i) return nums2[j + k - 1];
        int si = min((int)nums1.size(), i + k / 2), sj = j + k - k / 2;
        if (nums1[si - 1] > nums2[sj - 1])
            return find(nums1, i, nums2, sj, k - (sj - j));
        else
            return find(nums1, si, nums2, j, k - (si - i));
    }

};
原文地址:https://www.cnblogs.com/zykBlog/p/13875640.html