HDU 4891 The Great Pan

模拟题。

#include<map>
#include<set>
#include<ctime>
#include<cmath>
#include<queue>
#include<string>
#include<vector>
#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
#include<functional>
using namespace std;
#define ms(x,y) memset(x,y,sizeof(x))
#define rep(i,j,k) for(int i=j;i<=k;i++)
#define per(i,j,k) for(int i=j;i>=k;i--)
#define loop(i,j,k) for (int i=j;i!=-1;i=k[i])
#define inone(x) scanf("%d",&x)
#define intwo(x,y) scanf("%d%d",&x,&y)
#define inthr(x,y,z) scanf("%d%d%d",&x,&y,&z)
#define infou(x,y,z,p) scanf("%d%d%d%d",&x,&y,&z,&p)
#define lson x<<1,l,mid
#define rson x<<1|1,mid+1,r
#define mp(i,j) make_pair(i,j)
#define ft first
#define sd second
typedef long long LL;
typedef pair<int, int> pii;
const int low(int x) { return x&-x; }
const int INF = 0x7FFFFFFF;
const int mod = 1e9 + 7;
const int N = 4e5 + 10;
const double eps = 1e-10;

int n;
char t[5000010];
int p1,p2,ans;
int f;

void G()
{
    for(int i=0;t[i];i++)
    {
        if(t[i]!=' ')
        {
            if(f==1)
            {
                if(1LL*(p1+1)*ans<=100000) ans=(p1+1)*ans;
                else ans=100001;
            }
            p1=0;
        }

        if(t[i]=='{') p2=0;
        else if(t[i]=='}')
        {
            if(1LL*(p2+1)*ans<=100000) ans=(p2+1)*ans;
            else ans=100001;
        }
        else if(t[i]=='|') p2++;
        else if(t[i]==' ') p1++;
        else if(t[i]=='$')
        {
            f=f^1;
        }
    }
}

int main()
{
    while(~scanf("%d",&n))
    {
        getchar(); ans=1; f=p1=p2=0;
        while(n--)
        {
            gets(t); G();
        }

        if(ans>100000) printf("doge
");
        else printf("%d
",ans);

    }
    return 0;
}
原文地址:https://www.cnblogs.com/zufezzt/p/6516716.html