打印从1到最大的n位数

本题目考察大数。

#include <iostream>
#include <stdio.h>

using namespace std;


bool Increment(char * number)
{
    bool isOverflow = false;
    int nTakeOver = 0;
    int nLength = strlen(number);

    for (int i = nLength - 1; i >= 0; i--)  //模拟整数加法
    {
        int nSum = number[i] - '0' + nTakeOver;
        if (i == nLength - 1)
            nSum++;
        if (nSum >= 10)
        {
            if (i == 0)
            {
                isOverflow = true;
            }
            else
            {
                nSum -= 10;
                nTakeOver = 1;
                number[i] = char('0' + nSum);
            }
        }
        else
        {
            number[i] = char('0' + nSum);
            break;
        }
    }
    return isOverflow;
}

void PrintNumber(char * number)
{
    bool isBeginning0 = true;

    int nLength = strlen(number);
    for (int i = 0; i < nLength; ++i)
    {
        if (isBeginning0 && number[i] != '0')
            isBeginning0 = false;
        if (!isBeginning0)
        {
            printf("%c", number[i]);
        }
    }
    printf("	");
}


void Print1ToMaxOfNDigits(int n)
{
    if (n <= 0)
        return;
    char *number = new char[n + 1];
    memset(number, '0', n);
    number[n] = '';

    while (!Increment(number))
    {
        PrintNumber(number);
    }
    delete[]number;
}



int main()
{
    Print1ToMaxOfNDigits(2);

    cout << "hello..." << endl;
    system("pause");
    return 0;
}
原文地址:https://www.cnblogs.com/zmm1996/p/11874161.html