1+2+3+...+100用递归实现

# include <stdio.h>

long sum(int n)
{
    if (1 == n)
        return 1;
    else
        return n + sum(n-1);
}

int main(void)
{
    printf("%ld
", sum(100));

    return 0;
}
原文地址:https://www.cnblogs.com/zhujialei123/p/9630006.html