js中获取URL参数的共通方法getRequest()方法

        getRequest : function() {  

            var url = location.search; //获取url中"?"符后的字串

            var theRequest = new Object();

            if (url.indexOf("?") != -1) {

                var str = url.substr(1);

                strs = str.split("&");

                for(var i = 0; i < strs.length; i ++) {

                    theRequest[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1]); }

                }

            return theRequest;

        }
原文地址:https://www.cnblogs.com/zhangmm96/p/9841883.html