一个简易的加密算法
import java.util.HashMap; import java.util.Map; public class SecurityUtils { private static long slot = 自己指定的slot值; private static Map<String, String> map = new HashMap<>(); static { map.put("0", "m"); map.put("1", "q"); map.put("2", "e"); map.put("3", "t"); map.put("4", "u"); map.put("5", "o"); map.put("6", "a"); map.put("7", "d"); map.put("8", "g"); map.put("9", "j"); } private static Map<String, String> revserMap = new HashMap<>(); static { revserMap.put("m", "0"); revserMap.put("q", "1"); revserMap.put("e", "2"); revserMap.put("t", "3"); revserMap.put("u", "4"); revserMap.put("o", "5"); revserMap.put("a", "6"); revserMap.put("d", "7"); revserMap.put("g", "8"); revserMap.put("j", "9"); } public static String jiami(long orig){ long sum = orig + slot; String str = String.valueOf(sum); char[] chars = str.toCharArray(); StringBuilder newStr = new StringBuilder(); for (int i = 0; i < chars.length; i++){ newStr.append(map.get(String.valueOf(chars[i]))); } return newStr.toString(); } public static long jiemi(String str){ StringBuilder newStr = new StringBuilder(); char[] chars = str.toCharArray(); for (int i = 0; i < chars.length; i++){ newStr.append(revserMap.get(String.valueOf(chars[i]))); } long sum = Long.parseLong(newStr.toString()); return sum - slot; } public static void main(String[] args) { for(int i = 1; i < 11000000; i++) { long time = System.currentTimeMillis(); String jiami = jiami(i); long jiemi = jiemi(jiami); // System.out.println("耗时:" + (System.currentTimeMillis() - time)); if(jiemi == i){ System.out.println("加密:" + jiami + "揭秘:" + jiemi); }else { System.out.println("加密错误"); } } } }