PAT 甲级 1128 N Queens Puzzle (20 分)

思路:

1.行号唯一;
2.行号减列号唯一;

代码:

#include<iostream>
#include<map>
#include<vector>
using namespace std;
int main(){
	int k,n;
	scanf("%d",&k);
	for(int i=0;i<k;i++){
		scanf("%d",&n);
		map<int,int> mp;
		vector<int> v(2*n);
		int flag=1;
		for(int j=1;j<=n;j++){
			int row;
			scanf("%d",&row);
			if(mp[row]!=0) flag=0;
			mp[row]=j;
		}
		for(auto e:mp){
			if(v[e.first-e.second+n]!=0) flag=0;
			else v[e.first-e.second+n]=1;
		}
		printf(flag==1?"YES
":"NO
");
	}
	return 0;
}
原文地址:https://www.cnblogs.com/yuhan-blog/p/12309061.html