学习三种变换：Scaling, Rotation和Translation。
上学期修了Kobbelt教授（男神！）的图形学基础课，这部分内容已经接触过。
添加GLM库，直接给出齐次坐标系下的变换矩阵和相应的代码表示：
Scaling
(M=egin{bmatrix} a&0&0&0\ 0&b&0&0\ 0&0&c&0\ 0&0&0&1\ end{bmatrix})
glm::mat4 m = glm::scale(glm::mat4(1.0f), glm::vec3(a, b, c));
Rotation
绕x轴，( heta)表示旋转角度：
(M=egin{bmatrix}
1&0&0&0\
0&cos heta&-sin heta&0\
0&sin heta&cos heta&0\
0&0&0&1\
end{bmatrix})
glm::mat4 m = glm::rotate(glm::mat4(1.0f), glm::radians(theta), glm::vec3(1.0f, 0.0f, 0.0f));
绕y轴：
(M=egin{bmatrix}
cos heta&0&sin heta&0\
0&1&0&0\
-sin heta&0&cos heta&0\
0&0&0&1\
end{bmatrix})
glm::mat4 m = glm::rotate(glm::mat4(1.0f), glm::radians(theta), glm::vec3(0.0f, 1.0f, 0.0f));
绕z轴：
(M=egin{bmatrix}
cos heta&-sin heta&0&0\
sin heta&cos heta&0&0\
0&0&1&0\
0&0&0&1\
end{bmatrix})
glm::mat4 m = glm::rotate(glm::mat4(1.0f), glm::radians(theta), glm::vec3(0.0f, 0.0f, 1.0f));
绕任意轴（x, y, z），（x, y, z）为单位向量：
(M=egin{bmatrix}
cos heta+x^2(1-cos heta)&xy(1-cos heta)-zcos heta&xz(1-cos heta)+ycos heta&0\
yx(1-cos heta)+zcos heta&cos heta+y^2(1-cos heta)&yz(1-cos heta)-xcos heta&0\
zx(1-cos heta)-ycos heta&zy(1-cos heta)+xcos heta&cos heta+z^2(1-cos heta)&0\
0&0&0&1\
end{bmatrix})
glm::mat4 m = glm::rotate(glm::mat4(1.0f), glm::radians(theta), glm::vec3(x, y, z));
Translation
(M=egin{bmatrix} 1&0&0&t_x\ 0&1&0&t_y\ 0&0&1&t_z\ 0&0&0&1\ end{bmatrix})
glm::mat4 m = glm::translate(glm::mat4(1.0f), glm::vec3(tx, ty, tz));
在glm中，矩阵以column-major的顺序储存，即原变换矩阵的转置。以上述Translation代码为例，变换矩阵m的各元素索引为:
m[0][0] == 1.0f, m[0][1] == 0.0f, m[0][2] == 0.0f, m[0][3] == 0.0f
m[1][0] == 0.0f, m[1][1] == 1.0f, m[1][2] == 0.0f, m[1][3] == 0.0f
m[2][0] == 0.0f, m[2][1] == 0.0f, m[2][2] == 1.0f, m[2][3] == 0.0f
m[3][0] == tx, m[3][1] == ty, m[3][2] == tz, m[3][3] == 1.0f
练习
1.Using the last transformation on the container, try switching the order around by first rotating and then translating. See what happens and try to reason why this happens.
先Rotation，再Translation
新建transform.cpp和transform.h，并添加到工程中。定义一个transform函数返回变换矩阵：
transform.h
#ifndef TRANSFORM_H
#define TRANSFORM_H
#include <glm/glm/glm.hpp>
#include <glm/glm/gtc/matrix_transform.hpp>
#include <glm/glm/gtc/type_ptr.hpp>
#include <GLFW/glfw3.h>
#include <iostream>
glm::mat4 transform();
#endif // TRANSFORM_H
transform.cpp
#include "transform.h"
glm::mat4 transform()
{
glm::mat4 transMatrix = glm::mat4(1.0f);
transMatrix = glm::translate(transMatrix, glm::vec3(0.5f, -0.5f, 0.0f));
transMatrix = glm::rotate(transMatrix, glm::radians(45.0f), glm::vec3(0.0f, 0.0f, 1.0f));
return transMatrix;
}
修改Vertex Shader，定义uniform将变换矩阵传递到Shader中，对顶点坐标进行位置变换：
#version 330 core
layout (location = 0) in vec3 Pos;
layout (location = 1) in vec3 Col;
layout (location = 2) in vec2 Tex;
out vec4 Color;
out vec2 texCoord;
uniform mat4 transform;
void main()
{
gl_Position = transform * vec4(Pos, 1.0f);
Color = vec4(Col, 1.0f);
texCoord = Tex;
}
在渲染循环中添加一行代码，调用glUniformMatrix4fv函数更新uniform的值，即transform函数的返回值。glUniformMatrix4fv函数的第二和第三个参数分别表示矩阵的数量以及是否对矩阵转置：
glUniformMatrix4fv(glGetUniformLocation(ourShader.ID, "transform"), 1, GL_FALSE, glm::value_ptr(transform()));
先Translation，再Rotation
只需要修改transform.cpp:
#include "transform.h"
glm::mat4 transform()
{
glm::mat4 transMatrix = glm::mat4(1.0f);
transMatrix = glm::rotate(transMatrix, glm::radians(45.0f), glm::vec3(0.0f, 0.0f, 1.0f));
transMatrix = glm::translate(transMatrix, glm::vec3(0.5f, -0.5f, 0.0f));
return transMatrix;
}
2.Try drawing a second container with another call to glDrawElements but place it at a different position using transformations only. Make sure this second container is placed at the top-left of the window and instead of rotating, scale it over time.
在transform.cpp中定义transform2函数：
glm::mat4 transform2()
{
float timeValue = glfwGetTime();
float scaleValue = sin(timeValue)/2.0f+0.5f;
glm::mat4 transMatrix = glm::mat4(1.0f);
transMatrix = glm::translate(transMatrix, glm::vec3(-0.5f, 0.5f, 0.0f));
transMatrix = glm::scale(transMatrix, glm::vec3(scaleValue, scaleValue, 0.0f));
return transMatrix;
}