poj3692

题解:

对于每两个不认识的建边

然后求最大都立集

代码:

#include<cstdio>
#include<cstring>
#include<algorithm>
#include<cmath>
using namespace std;
const int N=205;
int n,m,k,a[N][N],match[N],f[N],x,y,cas;
int dfs(int x)
{
    for (int i=1;i<=m;i++)
     if (!a[x][i]&&!f[i])
      {
          f[i]=1;
          if (!match[i]||dfs(match[i]))
           {
               match[i]=x;
               return 1;
           }
      }
    return 0;  
}
int main()
{
    while (~scanf("%d%d%d",&n,&m,&k),n||m||k)
     {
         memset(a,0,sizeof a);
         printf("Case %d: ",++cas);
         memset(match,0,sizeof match);
         while (k--)scanf("%d%d",&x,&y),a[x][y]=1;
         int ans=0;
         for (int i=1;i<=n;i++)
          {
              memset(f,0,sizeof f);
              ans+=dfs(i);
          }
         printf("%d
",n+m-ans);
     }
}
原文地址:https://www.cnblogs.com/xuanyiming/p/8259889.html