最小生成树prim算法———模板

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#include<cstdio>
#include<cstring>
bool u[101];
int g[101][101],minn[101];
int main()
{
int n,m,q,p,total=0;
scanf("%d%d",&n,&m);
for (int i=1;i<=m;i++)
{
  scanf("%d%d",&q,&p);
  scanf("%d",&g[q][p]);
}
memset(minn,0x7f,sizeof(minn));   //初始化
minn[1]=0;
memset(u,1,sizeof(u));
for (int i=1;i<=n;i++)
{
  int k=0;
  for (int j=1;j<=n;j++)
  if (u[j]&&(minn[j]<minn[k]))
     k=j;
  u[k]=false;
  for (int j=1;j<=n;j++)
     if (u[j]&&(g[k][j]<minn[j]))
  minn[j]=g[k][j];
}
for (int i=1;i<=n;i++)
  total=total+minn[i];
printf("%d",total);
return 0;
}

原文地址:https://www.cnblogs.com/xiaoqi7/p/5084143.html