Android 再按一次退出程序

private long mExitTime = 0;

@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
if (keyCode == KeyEvent.KEYCODE_BACK && event.getAction() == KeyEvent.ACTION_DOWN) {
if ((System.currentTimeMillis() - mExitTime) > 2000) {
CommonUtil.showToast("再按一次退出程序", MainActivity.this);
mExitTime = System.currentTimeMillis();
} else {
finish();
System.exit(0);
}
return true;
}
return super.onKeyDown(keyCode, event);
}
原文地址:https://www.cnblogs.com/xiaobailook/p/8309120.html