HDU

题意：按要求输出。第一列是表示第几行。每行仅仅能有16个字节的字母，第二列是16进制的ASCII码。第三列大写和小写转换

思路：纯模拟，注意字母的十六进制是2位

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
const int MAXN = 5000;

char str[MAXN];

int main() {
	while (cin.getline(str, 4100)) {
		int len = strlen(str);
		for (int t = 0; t < len ; t += 16) {
			printf("%04x: ", t);
			for (int i = t; i < t+16; i += 2) {
				if (i < len)
					printf("%02x", str[i]);
				else printf("  ");
				if (i+1 < len)
					printf("%02x", str[i+1]);
				else printf("  ");
				printf(" ");
			}
			for (int i = t; i < len && i < t+16; i++) {
				if (str[i] >= 'a' && str[i] <= 'z')
					printf("%c", str[i]-'a'+'A');
				else if (str[i] >= 'A' && str[i] <= 'Z')
					printf("%c", str[i]-'A'+'a');
				else printf("%c", str[i]);
			}
			printf("
");
		}
	}
	return 0;
}