Vijos1164(CRT)

题目链接

分析:
CRT

tip

开ll,随时%

这里写代码片
#include<cstdio>
#include<cstring>
#include<iostream>
#define ll long long

using namespace std;

int n;
ll a[20],b[20],x,y;
ll M=1;

void exgcd(ll a,ll b)
{
    if (b==0)
    {
        x=1;y=0;
        return;
    }
    else {
        exgcd(b,a%b);
        int t=y;
        y=x-(a/b)*y;
        x=t;
    }
}

int main()
{
    scanf("%d",&n);
    ll ans=0;
    for (int i=1;i<=n;i++)
        scanf("%d%d",&a[i],&b[i]),
        M=M*a[i];
    for (int i=1;i<=n;i++)
    {
        ll Mi=M/a[i];
        exgcd(Mi,a[i]);
        ans=(ans%M+Mi%M*x%M*b[i]%M+M)%M;
    }
    printf("%lld",ans);
    return 0;
}
原文地址:https://www.cnblogs.com/wutongtong3117/p/7673219.html