561. Array Partition I(LeetCode)

Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible.

Example 1:

Input: [1,4,3,2]

Output: 4
Explanation: n is 2, and the maximum sum of pairs is 4.

Note:

  1. n is a positive integer, which is in the range of [1, 10000].
  2. All the integers in the array will be in the range of [-10000, 10000].
     1 #include<iostream>
     2 #include<vector>
     3 #include<algorithm>
     4 using namespace std;
     5 class Solution {
     6 public:
     7     int arrayPairSum(vector<int>& nums) {
     8         sort(nums.begin(), nums.end());
     9         int n = nums.size();
    10         int sum = 0;
    11         for (int i = 0; i < n; i += 2)
    12         {
    13             sum += nums[i];
    14         }
    15         return sum;
    16     }
    17 };
    18 int main()
    19 {
    20     vector<int> num{ 1, 4, 3, 2 };
    21     Solution s;
    22     cout << s.arrayPairSum(num) << endl;
    23     system("pause");
    24     return 0;
    25 }
原文地址:https://www.cnblogs.com/wujufengyun/p/6755838.html