1002. Find Common Characters

Given an array A of strings made only from lowercase letters, return a list of all characters that show up in all strings within the list (including duplicates).  For example, if a character occurs 3 times in all strings but not 4 times, you need to include that character three times in the final answer.

You may return the answer in any order.

开一个26大小的数组，然后对所有单词的字符统计出现过的次数，然后取min值。最后剩下来的就是共有的字符

class Solution(object):
    def commonChars(self, A):
        """
        :type A: List[str]
        :rtype: List[str]
        """
        count = [0] * 26
        for c in A[0]:
            count[ord(c) - ord('a')] += 1
        for s in A:
            temp_count = [0] * 26
            for c in s:
                temp_count[ord(c) - ord('a')] += 1
            for i in range(len(temp_count)):
                count[i] = min(count[i], temp_count[i])
        ans = []
        for i in range(len(count)):
            while count[i] > 0:
                ans.append(chr(i + ord('a')))
                count[i] -= 1
        return ans