迷宫 maze

 1 #include <stdlib.h>
 2 #include <stdio.h>
 3 
 4 #define stackinitsize 50
 5 #define stackincrement 8
 6 
 7 typedef struct {
 8     int x,y;
 9 }posttype;
10 
11 typedef struct {
12     int ord;
13     posttype seat;
14     int di;
15 }elemtype;
16 
17 typedef struct{
18   elemtype *base;
19   elemtype *top;
20   int stacksize;
21 }sqstack;
22 
23 
24 int  initstack(sqstack &s)
25   {s.base=(elemtype * ) malloc(stackinitsize*sizeof(elemtype));
26    s.top=s.base;
27    s.stacksize=stackinitsize;
28    return 1;
29    }
30 
31 int push(sqstack &s,elemtype e)
32  {
33    (*(s.top)).ord=e.ord;
34    (*(s.top)).seat.x=e.seat.x;
35    (*(s.top)).seat.y=e.seat.y;
36    (*(s.top)).di=e.di;
37    s.top++;
38    return 1;
39  }
40 
41 //elemtype gettop(sqstack s)
42 //{
43 //  return *(s.top-1);
44 // }
45 
46 int emptystack(sqstack s)
47   {if (s.top==s.base)  return 1;
48    else return 0;
49    }
50 
51 int pop(sqstack &s,elemtype &e)
52    { if (emptystack(s)) return 0;
53      --s.top;
54    e.ord=(*(s.top)).ord;
55    e.seat.x=(*(s.top)).seat.x;
56    e.seat.y=(*(s.top)).seat.y;
57    e.di=(*(s.top)).di;
58     return 1;
59      }


#include <stdio.h> # include "d:mazemystack.h" #define TRUE 1 #define FALSE 0 int a[10][10]={1,1,1,1,1,1,1,1,1,1, 1,0,0,1,0,0,0,1,0,1,
 1,0,0,1,0,0,0,1,0,1,
1,0,0,0,0,1,1,0,0,1,
1,0,1,1,1,0,0,0,0,1,
1,0,0,0,1,0,0,0,0,1,
1,0,1,0,0,0,1,0,0,1,
1,0,1,1,1,0,1,1,0,1,
1,1,0,0,0,0,0,0,0,1,
1,1,1,1,1,1,1,1,1,1};



typedef int Status; Status pass(posttype curpos) { if (a[curpos.x][curpos.y]==0) return 1; else return 0; } Status mazepath(int maze[10][10],posttype start,posttype end,sqstack &s) { int curstep; posttype curpos; elemtype e; initstack(s); curpos.x=start.x;curpos.y=start.y; curstep=1; do{ if(pass(curpos)) { // footprint(curpos);//stroe foot e.ord=curstep; e.seat.x=curpos.x; e.seat.y=curpos.y; e.di=1; push(s,e); if(curpos.x==end.x && curpos.y==end.y) return(TRUE); curpos.y=curpos.y+1;//east near curstep++; } else { if(!emptystack(s)) { pop(s,e); while(e.di==4 && !emptystack(s)) { // markprint(s.seat);//outprint reverse pop(s,e); }//end while if(e.di<4) { e.di++;push(s,e); switch(e.di) { case 1:curpos.y=curpos.y+1;break; case 2:curpos.x=curpos.x+1;break; case 3:curpos.y=curpos.y-1;break; case 4:curpos.x=curpos.x-1;break; } }//if(di<4) }//if(!emptystack(s)) }//else }while(!emptystack(s)); return FALSE; } void outputstak(sqstack s) { elemtype e; while(!emptystack(s)) { pop(s,e); printf("%d (%d,%d) %d ",e.ord,e.seat.x,e.seat.y,e.di); } } main() { posttype start,end; start.x=1;start.y=1; end.x=8;end.y=8; sqstack s1; if(mazepath(a,start,end,s1)==TRUE) outputstak(s1); else printf(" no path...."); }

  

原文地址:https://www.cnblogs.com/wc1903036673/p/3395113.html