Gym

Gym - 102163M
https://vjudge.net/problem/2356949/origin
取对数，然后特判特殊情况，就是0的那些情况

#include<iostream>
#include<cstdio>
#include<queue>
#include<algorithm>
#include<cmath>
#include<ctime>
#include<set>
#include<map>
#include<stack>
#include<cstring>
#define inf 2147483647
#define ls rt<<1
#define rs rt<<1|1
#define lson ls,nl,mid,l,r
#define rson rs,mid+1,nr,l,r
#define N 100010
#define For(i,a,b) for(int i=a;i<=b;i++)
#define p(a) putchar(a)
#define g() getchar()

using namespace std;
int T;
double a,b,c,d;
double eps=0.0000001;
void in(int &x){
    int y=1;
    char c=g();x=0;
    while(c<'0'||c>'9'){
        if(c=='-')y=-1;
        c=g();
    }
    while(c<='9'&&c>='0'){
        x=(x<<1)+(x<<3)+c-'0';c=g();
    }
    x*=y;
}
void o(int x){
    if(x<0){
        p('-');
        x=-x;
    }
    if(x>9)o(x/10);
    p(x%10+'0');
}
int main(){
    in(T);
    while(T--){
        cin>>a>>b>>c>>d;
        if((b==0&&d==0)||(a==0&&c==0)){
            cout<<"Lazy"<<endl;
            continue;
        }
        if(a==0&&c!=0){
            cout<<"Congrats"<<endl;
            continue;
        }
        if(c==0&&a!=0){
            cout<<"HaHa"<<endl;
            continue;
        }
        if(fabs(b*log(a)-d*log(c))<eps)
            cout<<"Lazy"<<endl;
        else
            if(b*log(a)-d*log(c)<0)
                cout<<"Congrats"<<endl;
        else
            cout<<"HaHa"<<endl;
    }
    return 0;
}