a letter and a number

时间限制：3000 ms | 内存限制：65535 KB

难度：1

描述: we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

输入

On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).

输出

for each case, you should the result of y+f(x) on a line

样例输入

6
R 1
P 2
G 3
r 1
p 2
g 3

样例输出

代码如下：

#include<stdio.h>
#include<string.h>
int main()
{
int n,m;
char c;
scanf("%d",&n);
while(n--)
{
  getchar();
  scanf("%c",&c);
  scanf("%d",&m);
  if(c>='a'&&c<='z')
   printf("%d ",96-c+m);
  if(c>='A'&&c<='Z')
   printf("%d ",c-64+m);
}
return 0;
}