数组翻转

    int a[]={1,2,4,6,7,0};
    int n=sizeof(a)/sizeof(int);
   
    //翻转
    for (int i=0;i<n;i++)
    {
        if (i<n-1-i)
        {
            int s=a[i];
            a[i]=a[n-1-i];
            a[n-1-i]=s;
        }
      
    }
    for (int i=0; i<n; i++)
    {
        printf("%d",a[i]);
    }

原文地址:https://www.cnblogs.com/wangjinshan/p/7080225.html