补题补题补题~~~~really big numbers

不是啥难题,直接上代码吧。
#i #include<stdio.h>
#include<string.h>
#include<math.h>
#include<stdlib.h>

int  BigNumbers(long long n)
{
	int sum = 0;
	while(n>0)
	{
		sum += n%10;
		n /= 10;
	}
	return sum;
}

int main()
{
	long long N,S;
	scanf("%lld %lld",&N,&S);
	for(long long i=S+1 ; i<=N ; i++)
	{
		if(i - BigNumbers(i)>=S){
			printf("%lld",N-i+1);
			return 0;
		}
		else if(i == S+162){
			printf("%lld",N-i+1);
			return 0;
		}
	}
	printf("0");
	return 0;
}

            
原文地址:https://www.cnblogs.com/vocaloid01/p/9514318.html