Compare Version Numbers

 1 typedef struct Version
 2 {
 3     vector<int> vec;
 4 }Version;
 5 int cmp(Version a,Version b)
 6 {
 7     int i;
 8     int la=a.vec.size(),lb=b.vec.size();
 9     for(i=0;i<la&&i<lb;i++)
10     {
11         if(a.vec[i]!=b.vec[i])
12             return a.vec[i]>b.vec[i]?1:-1;
13     }
14     if(la!=lb)
15         return la>lb?1:-1;
16     return 0;
17 }
18 class Solution {
19 public:
20     int compareVersion(string version1, string version2) {
21         Version v1=toDouble(version1);
22         Version v2=toDouble(version2);
23         return cmp(v1,v2);
24     }
25     Version toDouble(string v)
26     {
27         int n=v.size(),i;
28         int ans=0;
29         Version ver;
30         ver.vec.clear();
31         for(i=0;i<n;i++)
32         {
33             if(isdigit(v[i]))
34             {
35                 ans=ans*10+v[i]-'0';
36             }
37             else
38             {
39                 ver.vec.push_back(ans);
40                 ans=0;
41             }
42         }
43         ver.vec.push_back(ans);
44         for(i=ver.vec.size()-1;i>0;i--)
45         {
46             if(ver.vec[i]==0)
47                 ver.vec.pop_back();
48             else
49                 break;
50         }
51         return ver;
52     }
53 };

View Code

非常纠结的一道题，对于版本号 1.0>0.1 , 1.0=1, 0.0.1<0.1,

可以有多个point,但是不考虑末位0.

将字符串转化为整数stoi(str);