Lamda所有的Capture均是引用

【Lamda所有的Capture均是引用】

　　下面的程序，两个lambda 引用的实际上是同一个a、b。连int都能引用了，说明Lambda对所有类型都是以引用来处理。

 1 int a = 0;
 2         int b = 1;
 3         Func<int> exe = ()=>{
 4             int tmp = a;
 5             a = b;
 6             b = tmp+b;
 7             return a;
 8         };
 9         Debug.Log("a1 = " + exe());
10         Debug.Log("a2 = " + exe());
11         Debug.Log("a3 = " + exe());
12         Debug.Log("a4 = " + exe());
13         Debug.Log("a5 = " + exe());
14 
15         Func<int> exe2 = ()=>{
16             int tmp = a;
17             a = b;
18             b = tmp+b;
19             return a;
20         };
21         Debug.Log("a1 = " + exe2());
22         Debug.Log("a2 = " + exe2());
23         Debug.Log("a3 = " + exe2());
24         Debug.Log("a4 = " + exe2());
25         Debug.Log("a5 = " + exe2());

　　结果为：