n的幂

题目:给你一个数n,判断n是不是某个数的幂,,这个数题目里会给出,leetCode上有三道题,分别是2的幂,3的幂,4的幂

思路:方法都一样,while循环而已

//2的幂
public class Solution {
    public boolean isPowerOfFour(int num) {
        if(num>1){
            while(num%2==0)
                num/=2;
        }
        return num==1;
    }
}
//3的幂
public class Solution {
    public boolean isPowerOfFour(int num) {
        if(num>1){
            while(num%3==0)
                num/=3;
        }
        return num==1;
    }
}
//4的幂
public class Solution {
    public boolean isPowerOfFour(int num) {
        if(num>1){
            while(num%4==0)
                num/=4;
        }
        return num==1;
    }
}
原文地址:https://www.cnblogs.com/team42/p/6890962.html