Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
对mxn的格子扫一遍,每个格子的值等于上方和左方格子值中较小的
class Solution { public: int minPathSum(vector<vector<int> > &grid) { // Start typing your C/C++ solution below // DO NOT write int main() function if(grid.size()==0||grid[0].size()==0)return 0; for(int i=1;i<grid.size();i++){ grid[i][0]+=grid[i-1][0]; } for(int j=1;j<grid[0].size();j++){ grid[0][j]+=grid[0][j-1]; } for(int i=1;i<grid.size();i++){ for(int j=1;j<grid[i].size();j++){ grid[i][j]=min(grid[i-1][j],grid[i][j-1])+grid[i][j]; } } return grid[grid.size()-1][grid[0].size()-1]; } };