几个极限的证明

(求证:lim_{n o infty }frac{1}{n^alpha}=0,alpha>0)
(证明:)
(分为两种情况考虑,情况1:alpha>=1,情况2:alpha<1)
(情况1:当alphageq 1)
(|frac{1}{n^alpha}-0|=frac{1}{n^alpha}<frac{1}{n})
(若需frac{1}{n}<epsilon)
(即n>frac{1}{epsilon},即可)
(即,取N=[frac{1}{epsilon}]+1)
(则当quad n>N时,即有quad frac{1}{n} < frac{1}{N}<epsilon)

原文地址:https://www.cnblogs.com/strongdady/p/13879027.html